{"id":353,"date":"2020-08-15T20:49:02","date_gmt":"2020-08-15T18:49:02","guid":{"rendered":"https:\/\/acertijosparati.com\/acertijos\/?p=353"},"modified":"2021-03-28T22:58:56","modified_gmt":"2021-03-28T20:58:56","slug":"acertijo-30-pensamiento-visual-en-practica","status":"publish","type":"post","link":"https:\/\/erickjrp.com\/acertijos\/acertijo-30-pensamiento-visual-en-practica\/","title":{"rendered":"Acertijo #30: Pensamiento visual en pr\u00e1ctica"},"content":{"rendered":"\n<p style=\"font-size:18px\">En esta oportunidad, traemos dos acertijos muy diferentes a los que usualmente presentamos en Acertijos Para Ti. Con ellos, pondremos a prueba nuestra capacidad de observaci\u00f3n y deducci\u00f3n.<\/p>\n\n\n\n<p class=\"margin-bottom-0\" style=\"font-size:18px\">Sin m\u00e1s que agregar, \u00a1veamos los acertijos!<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>1 &#8211; Del 1 al 11<\/strong><\/h2>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"576\" src=\"https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/Slide2-1024x576.png\" alt=\"Acertijo #30 - Del 1 al 11\" class=\"wp-image-2789\" srcset=\"https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/Slide2-1024x576.png 1024w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/Slide2-300x169.png 300w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/Slide2-768x432.png 768w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/Slide2.png 1280w\" sizes=\"auto, (max-width: 767px) 89vw, (max-width: 1000px) 54vw, (max-width: 1071px) 543px, 580px\" \/><\/figure>\n\n\n\n<p class=\"margin-bottom-0\" style=\"font-size:18px\">\u00bfPuedes acomodar los n\u00fameros del 1 al 11 (a excepci\u00f3n del 6) en los c\u00edrculos, de manera que los dos n\u00fameros que est\u00e1n en cada l\u00ednea recta sumen siempre lo mismo?<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>2 &#8211; Tri\u00e1ngulo de monedas<\/strong><\/h2>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"576\" src=\"https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/Slide3-1024x576.png\" alt=\"\" class=\"wp-image-2790\" srcset=\"https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/Slide3-1024x576.png 1024w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/Slide3-300x169.png 300w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/Slide3-768x432.png 768w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/Slide3.png 1280w\" sizes=\"auto, (max-width: 767px) 89vw, (max-width: 1000px) 54vw, (max-width: 1071px) 543px, 580px\" \/><\/figure>\n\n\n\n<p class=\"margin-bottom-0\" style=\"font-size:18px\">Tenemos diez monedas en forma de tri\u00e1ngulo. \u00bfC\u00f3mo poner el tri\u00e1ngulo cabeza abajo moviendo s\u00f3lo tres monedas?<\/p>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<!-- Inner content 1 -->\n<ins class=\"adsbygoogle mb-4\" style=\"display:block\" data-ad-client=\"ca-pub-6237324477943455\" data-ad-slot=\"2342947293\" data-ad-format=\"auto\" data-full-width-responsive=\"true\"><\/ins>\n<script>\n     jQuery(document).ready(function(){\n      (adsbygoogle = window.adsbygoogle || []).push({});\n     })\n<\/script>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Aclaratorias<\/strong><\/h2>\n\n\n\n<p style=\"font-size:18px\">En el acertijo <em><strong>Del 1 al 11<\/strong><\/em>, vemos que cada c\u00edrculo est\u00e1 identificado con una letra. La idea es que a cada letra le asignemos un valor num\u00e9rico (entre el n\u00famero 1 y 11, sin repetir ninguno y sin usar el n\u00famero 6).<\/p>\n\n\n\n<p style=\"font-size:18px\">Tal como se aprecia en la imagen: el resultado de la suma de los dos n\u00fameros pertenecientes a cada una de las rectas, debe ser el mismo.<\/p>\n\n\n\n<p style=\"font-size:18px\">Por lo que, por ejemplo: A + F = B + G.<\/p>\n\n\n\n<p style=\"font-size:18px\">En el acertijo <em><strong>Tri\u00e1ngulo de monedas<\/strong><\/em> debemos, con s\u00f3lo hacer tres movimientos, lograr que el tri\u00e1ngulo que se ve en la parte izquierda de la imagen, quede boca abajo.<\/p>\n\n\n\n<p style=\"font-size:18px\">En la parte derecha de la imagen se ve el tri\u00e1ngulo original pero rodeado de casillas circulares que contienen letras. La idea es que, vali\u00e9ndonos de estos espacios, movamos tres monedas y as\u00ed lograr voltear el tri\u00e1ngulo.<\/p>\n\n\n\n<p class=\"margin-bottom-0\" style=\"font-size:18px\">Para plantear la soluci\u00f3n, basta con escribir, por ejemplo: \u00abMoneda 5 a la posici\u00f3n L\u00bb, con los tres movimientos permitidos.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>De vuelta al acertjo #30 de Acertijos Para Ti<\/strong><\/h2>\n\n\n\n<p style=\"font-size:18px\">El 80% del cerebro est\u00e1 dise\u00f1ado para asimilar y procesar im\u00e1genes, por lo que supone menos esfuerzo que leer un texto. De ah\u00ed radica el \u00e9xito del pensamiento visual y su creciente utilizaci\u00f3n en los \u00faltimos a\u00f1os.<\/p>\n\n\n\n<p style=\"font-size:18px\">Dicho esto, es momento de poner a prueba tu capacidad visual y l\u00f3gica.<\/p>\n\n\n\n<p style=\"font-size:18px\">\u00a1Vamos a ello!<\/p>\n\n\n\n<h3 class=\"font-size-16 color-gray wp-block-heading\"><strong>Si ya has podido resolver el Acertijo #30 de Acertijos Para Ti, presiona el bot\u00f3n \u00ab\u00a1Ver respuesta!\u00bb y chequea si est\u00e1s en lo correcto:<\/strong><\/h3>\n\n\n\n<script async=\"\" src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<!-- Inner content 2 -->\n<ins class=\"adsbygoogle mb-4\" style=\"display:block\" data-ad-client=\"ca-pub-6237324477943455\" data-ad-slot=\"2757880260\" data-ad-format=\"auto\" data-full-width-responsive=\"true\"><\/ins>\n<script>\n     jQuery(document).ready(function(){\n      (adsbygoogle = window.adsbygoogle || []).push({});\n     })\n<\/script>\n\n\n<p id=\"collapse-button-own\" style=\"text-align: center;\"><input type='hidden' bg_collapse_expand='69f1a58bf2a747020700184' value='69f1a58bf2a747020700184'><input type='hidden' id='bg-show-more-text-69f1a58bf2a747020700184' value='\u00a1Ver respuesta!'><input type='hidden' id='bg-show-less-text-69f1a58bf2a747020700184' value='Esconder respuesta'><button id='bg-showmore-action-69f1a58bf2a747020700184' class='bg-showmore-plg-button bg-blue-button  '   style=\" color:#FFFFF;\">\u00a1Ver respuesta!<\/button><div id='bg-showmore-hidden-69f1a58bf2a747020700184' ><\/p>\n<div id=\"contenido-solucion\">\n<h2><strong>1 &#8211; Del 1 al 11<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-2801 size-full\" title=\"Acertijo #30 - Del 1 al 11 - Respuesta\" src=\"https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/5.png\" alt=\"Acertijo #30 - Del 1 al 11 - Respuesta\" width=\"1280\" height=\"720\" srcset=\"https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/5.png 1280w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/5-300x169.png 300w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/5-1024x576.png 1024w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/5-768x432.png 768w\" sizes=\"auto, (max-width: 767px) 89vw, (max-width: 1000px) 54vw, (max-width: 1071px) 543px, 580px\" \/><\/p>\n<p>Tal como se observa en la imagen, s\u00f3lo debemos emparejar el n\u00famero m\u00e1s peque\u00f1o (1) con el m\u00e1s grande (11) y continuar, en orden creciente, a partir del n\u00famero m\u00e1s peque\u00f1o, y en orden decreciente desde el n\u00famero m\u00e1s grande.<\/p>\n\n<!-- GOOGLE AD -->\n<div id=\"ad-inner-content-3\"><\/div>\n\njQuery(\"#collapse-button-own\").on(\"click\", function(){\n  setTimeout(function() {\n    if(jQuery(\"#ad-inner-content-3\").html().trim() !== \"\") { return; }\n    \/\/ script\n    var adScript = document.createElement(\"script\");\n    adScript.type = \"text\/javascript\";\n    adScript.src = \"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\";\n    adScript.async = \"true\";\n    jQuery(\"#ad-inner-content-3\").append(adScript);\n    \/\/ element\n    var adElement = document.createElement(\"ins\");\n    adElement.setAttribute(\"class\", \"adsbygoogle mb-4\");\n    adElement.setAttribute(\"style\", \"display:block\");\n    adElement.setAttribute(\"data-ad-client\", \"ca-pub-6237324477943455\");\n    adElement.setAttribute(\"data-ad-slot\", \"7675165028\");\n    adElement.setAttribute(\"data-ad-format\", \"auto\");\n    adElement.setAttribute(\"data-full-width-responsive\", \"true\");\n    jQuery(\"#ad-inner-content-3\").append(adElement);\n    \/\/ init\n    jQuery(document).ready(function(){\n      (adsbygoogle = window.adsbygoogle || []).push({});\n    });\n  }, 1000);\n});\n\n<!-- FINALIZA GOOGLE AD -->\n\n<p class=\"margin-bottom-0\">Por supuesto, la ubicaci\u00f3n de cada l\u00ednea recta en el c\u00edrculo no es fija, por lo que si has solucionado este acertjo y, sin embargo, lo ves un poco diferente, no significa que no sea una soluci\u00f3n correcta. Lo importante es que cada l\u00ednea sume 12, tal como se ve en la imagen.<\/p>\n<h2><strong>2 &#8211; Tri\u00e1ngulo de monedas<\/strong><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2802 size-full\" title=\"Acertijo #30 - Tri\u00e1ngulo de monedas - Respuesta\" src=\"https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/6.png\" alt=\"Acertijo #30 - Tri\u00e1ngulo de monedas - Respuesta\" width=\"1280\" height=\"720\" srcset=\"https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/6.png 1280w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/6-300x169.png 300w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/6-1024x576.png 1024w, https:\/\/erickjrp.com\/acertijos\/wp-content\/uploads\/2020\/08\/6-768x432.png 768w\" sizes=\"auto, (max-width: 767px) 89vw, (max-width: 1000px) 54vw, (max-width: 1071px) 543px, 580px\" \/><\/p>\n<p class=\"margin-bottom-10\">Para resolver este acertijo visual, s\u00f3lo debemos realizar los siguientes tres movimientos:<\/p>\n<ul class=\"ul-normal font-size-18 padding-top-5 margin-bottom-10\">\n<li>Moneda 0 a posici\u00f3n K.<\/li>\n<li>Moneda 6 a posici\u00f3n E.<\/li>\n<li>Moneda 9 a posici\u00f3n F.<\/li>\n<\/ul>\n<p class=\"margin-bottom-0\">Con estos movimientos, tal como vemos en la parte derecha de la imagen, hemos logrado posicionar boca abajo el tri\u00e1ngulo planteado inicialmente.<\/p>\n\n<!-- GOOGLE AD -->\n<div id=\"ad-inner-content-4\"><\/div>\n\njQuery(\"#collapse-button-own\").on(\"click\", function(){\n  setTimeout(function() {\n    if(jQuery(\"#ad-inner-content-4\").html().trim() !== \"\") { return; }\n    \/\/ script\n    var adScript = document.createElement(\"script\");\n    adScript.type = \"text\/javascript\";\n    adScript.src = \"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\";\n    adScript.async = \"true\";\n    jQuery(\"#ad-inner-content-4\").append(adScript);\n    \/\/ element\n    var adElement = document.createElement(\"ins\");\n    adElement.setAttribute(\"class\", \"adsbygoogle mb-4\");\n    adElement.setAttribute(\"style\", \"display:block\");\n    adElement.setAttribute(\"data-ad-client\", \"ca-pub-6237324477943455\");\n    adElement.setAttribute(\"data-ad-slot\", \"5867259335\");\n    adElement.setAttribute(\"data-ad-format\", \"auto\");\n    adElement.setAttribute(\"data-full-width-responsive\", \"true\");\n    jQuery(\"#ad-inner-content-4\").append(adElement);\n    \/\/ init\n    jQuery(document).ready(function(){\n      (adsbygoogle = window.adsbygoogle || []).push({});\n    });\n  }, 1000);\n});\n\n<!-- FINALIZA GOOGLE AD -->\n\n<h2><strong>Conclusi\u00f3n acertijo #30 de Acertijos Para Ti<\/strong><\/h2>\n<p>Esperamos haya sido de tu agrado el poner a prueba tu capacidad visual con estos interesantes y entretenidos acertijos visuales.&nbsp;<\/p>\n<p>Pronto tendremos m\u00e1s acertijos de este estilo. \u00a1Nos vemos en el siguiente \ud83d\ude03!<\/p>\n<\/div>\n<p><\/div><\/p>\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p><em><em>Si tienes alguna duda respecto al planteamiento y\/o soluci\u00f3n del Acertijo #30 de <a rel=\"noreferrer noopener\" href=\"https:\/\/www.instagram.com\/acertijosparati\/\" target=\"_blank\">Acertijos Para Ti<\/a>, por favor, deja un comentario y de inmediato solventaremos tus inquietudes. Tambi\u00e9n puedes usar el formulario de <a rel=\"noreferrer noopener\" href=\"https:\/\/erickjrp.com\/acertijos\/contacto\/\" target=\"_blank\">contacto<\/a> para enviar un mensaje privado.<\/em><\/em><\/p>\n","protected":false},"excerpt":{"rendered":"<p>En esta oportunidad, traemos dos acertijos muy diferentes a los que usualmente presentamos en Acertijos Para Ti. Con ellos, pondremos<\/p>\n<div class=\"read-more\"><a href=\"https:\/\/erickjrp.com\/acertijos\/acertijo-30-pensamiento-visual-en-practica\/\" class=\"link\">Leer m\u00e1s <i class=\"fa fa-angle-right\"><\/i><span class=\"screen-reader-text\"> \u00abAcertijo #30: Pensamiento visual en pr\u00e1ctica\u00bb<\/span><\/a><\/div>\n","protected":false},"author":1,"featured_media":2796,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[1,12,13],"tags":[7],"class_list":["post-353","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-acertijos-logicos","category-acertijos-numericos","category-acertijos-visuales","tag-acertijos-faciles"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Acertijo #30: Pensamiento visual en pr\u00e1ctica - 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